Hey! I have this problem - i'm currently working on Quadratics at school, and i got homework. One of the questions is 18^2+2px+32. I have to find the Value of P, the answer i got is P>+-24. Can someone please confirm this is correct?

fix the typos

And what does p>+-24 mean. I get that +- means ±, but what does p>±24 mean?

Also what are you supposed to do with

18x^2+2px+32

?? factor it? solve for the roots? find p such that it is a perfect square? what, oh, what? Wooooeeee is meeee!!

To find the range of possible values for P in the equation 18^2 + 2px + 32, we can use the concept of discriminant from quadratic equations.

The discriminant (D) helps in determining the nature of the roots of a quadratic equation and is calculated using the formula D = b^2 - 4ac, where a, b, and c are the coefficients of the quadratic equation in the form ax^2 + bx + c = 0.

In this equation, a = 18^2, b = 2p, and c = 32. Substituting these values into the discriminant formula, we get:

D = (2p)^2 - 4(18^2)(32)
D = 4p^2 - 4(18^2)(32)
D = 4p^2 - 4(324)(32)
D = 4p^2 - 41472

Now, for the equation to have any real roots, the discriminant D must be greater than or equal to zero. Therefore, we have:

4p^2 - 41472 >= 0

Simplifying the inequality:

4p^2 >= 41472
p^2 >= 10368
p >= sqrt(10368)
p >= +- 102

Hence, the value of P for which the equation 18^2 + 2px + 32 has real roots is P >= -102 and P <= 102.

Therefore, the statement "P > +/- 24" is incorrect. Please note that the expression "P > +/- 24" suggests that P should be greater than 24 or less than -24, but the correct range is P >= -102 and P <= 102.