The binding energy of election is 13.6 v .the loss of mass in formation of h atom is
To calculate the loss of mass in the formation of a hydrogen atom, we need to use Einstein's famous equation, E=mc^2, where E represents energy, m represents mass, and c represents the speed of light.
In this case, the energy given is 13.6 eV (electron volts), which we need to convert to joules since the equation requires energy in SI units. 1 eV is equal to 1.6 x 10^-19 joules, so 13.6 eV is:
13.6 eV * 1.6 x 10^-19 J/eV = 2.18 x 10^-18 J
Now, we know the energy released during the formation of a hydrogen atom, but we need to find the mass lost.
Rearranging the equation E=mc^2, we can solve for m:
m = E / c^2
First, we need to convert the speed of light (c) from meters per second (m/s) to centimeters per second (cm/s) for consistency with SI units. The speed of light is approximately 3 x 10^8 m/s, which is equal to:
3 x 10^8 m/s * 100 cm/m = 3 x 10^10 cm/s
Now we can calculate the mass lost:
m = (2.18 x 10^-18 J) / (3 x 10^10 cm/s)^2
Simplifying the equation:
m = (2.18 x 10^-18 J) / (9 x 10^20 cm^2/s^2)
m ≈ 2.42 x 10^-38 grams
Therefore, the loss of mass in the formation of a hydrogen atom is approximately 2.42 x 10^-38 grams.