How would NaHCO3 dissociate in water for a beaker diagram? Would it be Na+ and HCO3-
I don't know what you mean for a "beaker diagram" but yes, that's the way NaHCO3 dissociates.
thank you
To determine the dissociation of NaHCO3 (sodium bicarbonate) in water for a beaker diagram, we need to understand the way in which the compound dissociates.
When NaHCO3 is added to water, it will dissociate into its constituent ions. The Na (sodium) cation will separate from the HCO3 (bicarbonate) anion.
The dissociation of NaHCO3 can be represented as follows:
NaHCO3 (s) → Na+ (aq) + HCO3- (aq)
In this representation, the (s) signifies that NaHCO3 is in solid form, and (aq) indicates that the ions Na+ and HCO3- are in aqueous (dissolved) state.
The sodium ion (Na+) and the bicarbonate ion (HCO3-) are then free to move around in the water, making the solution electrically conductive.
Therefore, in a beaker diagram, you can depict NaHCO3 dissociating in water as separate ions Na+ and HCO3- dispersed in the aqueous solution.