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find the next three terms in 18,27,36,45
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54, 63 , 72
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find X if the numbers X+3, 5x-3, and 7x+3 are three consecutive terms of a G.P of positive terms. with this value X and given
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If GP, then (5x-3)/(x+3) = (7x+3)/(5x-3) 25x^2 - 30x + 9 = 7x^2 + 24x + 9 18x^2 - 54x = 0 6x(3x - 9)
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The first and last terms of an a.p are 79 and 5 and it's sum is 814 find(a) the number of terms in the a.p(b)the common
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What is your school subject? It's not the name of your school.
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1) The sum of last three terms of GP having n terms is 1024 time the sume of first 3 terms of GP. If 3rd term is 5. Find the
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(1) ar^(n-1) + ar^(n-2) + ar^(n-3) = 1024 (a + ar + ar^2) ar^(n-3) (1 + r + r^2) = 1024a (1 + r +
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when you are multiplying an equation how do you find like terms
The ones that look alike. The numbers are like terms such as 4 or
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To find like terms when multiplying equations, you need to identify terms that have the same
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please help i have done these problems 3 times now and always get them worng.
find the first three terms of (a-b)^6 find the last
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I want to see your work on one. The binomial expansion is pretty straightforward.
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in right triangle ABC, the altitude CD is drawn to hypotynuse AB. The length of DB is 5 units longer than AD.
a) If AD = x,
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To find the answers, we will use the properties of right triangles and proportions. Let's go step by
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The first three terms of a GP are also the first,nineth and eleventh terms respectively of an AP. Given that the terms of the GP
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I don’t get this solution ;—;
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1.Find an A.P. such that the sum of the first three terms is one half the sum of the next four terms,the first term being 12.
2.I
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Just use the definitions of an AP and translate the English to Math. "the sum of the first three
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Three consecutive terms of an arithmetic sequence have a sum of 12 and a product of -80 .Find the terms. [hint : let the terms
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so, follow the hint. add them and multiply them.
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The first and 5th terms of an exponential sequence are 16 and 9 respectively. Find the 7th terms of the sum of the first 7 terms
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from your data: a = 16 ar^4 = 9 16r^4 = 9 r^4 = 9/16 r^2 = ± 3/4 , but assuming r is real, r^2 =
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