A student pulls a 5kg wagon with a constant speed of 1m/s along a horizontal surface. The force of friction between the wagon and the surface is 10N. What is the applied force?

The speed is constant (no acceleration) so there is no net force on the wagon. Therefore the horizontal pull is 10 N to exactly balance the friction force.

thanks!!

To find the applied force, we can start by using Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the wagon is moving with a constant speed, so its acceleration is zero.

The equation of Newton's second law can be written as:
Net force = mass * acceleration

Since the wagon is moving at a constant speed, there is no acceleration. Therefore, the net force acting on the wagon is zero. This means that the applied force must balance the force of friction in order to keep the wagon moving at a constant speed.

The force of friction between the wagon and the surface is given as 10N. According to Newton's third law of motion, the force of friction will be equal in magnitude but opposite in direction to the applied force. Therefore, the applied force must also be 10N for the wagon to move with a constant speed.

So, the applied force is 10N.