how do i solve this G(t)=4t+1 find the following G(2)=, G(-10)=, G(6.9)=
g(2) = 4(2) + 1 = 9
just substitute the number in perinthases for t.
given the function G(t)=4t+1 find each of the following G(2)=, G(-10)=, G(6.9)= plz help me don't understand this
Subsitute the 2 for the t, and then the -10, then the 6.9 so you get:
g(2) = 4(2) + 1 = 9
g(-10) = 4(-10) + 1 = -39
g(6.9) = 4(6.9) + 1 = 28.6
:D
To find the values of G(t) for the given inputs, you need to substitute the values of t into the equation G(t) = 4t + 1. Let's solve it step by step:
1. G(2):
To find G(2), substitute t = 2 into the equation.
G(2) = 4(2) + 1
= 8 + 1
= 9
Therefore, G(2) = 9.
2. G(-10):
To find G(-10), substitute t = -10 into the equation.
G(-10) = 4(-10) + 1
= -40 + 1
= -39
Therefore, G(-10) = -39.
3. G(6.9):
To find G(6.9), substitute t = 6.9 into the equation.
G(6.9) = 4(6.9) + 1
= 27.6 + 1
= 28.6
Therefore, G(6.9) = 28.6.
So, the answers are:
G(2) = 9,
G(-10) = -39,
G(6.9) = 28.6.