A car accelerates uniformly in a straight line
from rest at the rate of 3.6 m/s2
.
What is the speed of the car after it has
traveled 61 m?
Answer in units of m/s
V^2 = Vo^2 + 2a*d.
Vo = 0, a = 3.6 m/s^2, d = 61 m.,
V = ?.
To find the speed of the car after it has traveled 61 m, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity (in this case, the car starts from rest, so u = 0)
a = acceleration
s = displacement
Plugging in the values we have:
u = 0 m/s
a = 3.6 m/s^2
s = 61 m
v^2 = 0^2 + 2 * 3.6 * 61
v^2 = 0 + 439.2
v^2 = 439.2
To find the value of v, we need to take the square root of both sides:
v = sqrt(439.2)
Calculating this value, we get:
v ≈ 20.95 m/s
Therefore, the speed of the car after it has traveled 61 m is approximately 20.95 m/s.