1. Select all the values of x that will make the following inequality true.
2(3x − 6) ≥ 5x − 10
x = -5
x = 1
x = 0
x = 2
x = 13
x = 7
how do i do this
Which of the following values of x would make 3x and x + 10 equal?
A. x = 2
B. x= 4
C. x= 5
D. x= 6
M >0
To solve the inequality 2(3x - 6) ≥ 5x - 10, we need to isolate the variable x. Let's step through the solution:
1. Distribute the 2 through the parentheses: 6x - 12 ≥ 5x - 10
2. Collect like terms by subtracting 5x from both sides: 6x - 5x - 12 ≥ 5x - 5x - 10
Simplifying gives: x - 12 ≥ -10
3. Add 12 to both sides to isolate x: x - 12 + 12 ≥ -10 + 12
Simplifying gives: x ≥ 2
Therefore, the values of x that make the inequality true are x ≥ 2.
Now let's evaluate each given option:
1. x = -5: -5 is less than 2, so it is not a solution.
2. x = 1: 1 is less than 2, so it is not a solution.
3. x = 0: 0 is less than 2, so it is not a solution.
4. x = 2: 2 is equal to 2, so it is a solution.
5. x = 13: 13 is greater than 2, so it is a solution.
6. x = 7: 7 is greater than 2, so it is a solution.
Therefore, the values of x that will make the inequality true are x = 2, x = 13, and x = 7.
x>=2
I've been stuck on this one problem.
see earlier post
Select all answers that make the following inequality true.
LaTeX: 4N-19>17