How to construct a Triangle ABC in which base BC=4.8 cm, Angle B=90° and hypotenuse AC=6.2 cm.
To construct a triangle ABC with the given conditions, follow these steps:
Step 1: Draw a line segment AB = 4.8 cm. This will be the base of the triangle.
Step 2: From point B, construct a perpendicular line to AB. This can be done using a compass or a set square. Label the point where the perpendicular line intersects AB as point D.
Step 3: With point B as the center, draw an arc with a radius of 6.2 cm. This arc will intersect the perpendicular line at point C.
Step 4: Draw the line segments AC and BC.
Step 5: Label point A where lines AC and AB intersect.
Step 6: Your triangle ABC is now constructed as ABC, where BC = 4.8 cm, angle B = 90°, and AC = 6.2 cm.
Note: Since angle B is a right angle (90°), triangle ABC is a right triangle. The side opposite the right angle is called the hypotenuse (AC in this case).
To construct a Triangle ABC with a base BC=4.8 cm, Angle B=90°, and hypotenuse AC=6.2 cm, follow these steps:
1. Draw a straight line segment and mark a point A on it. This will be the vertex of the right angle.
2. Using a compass, measure a length of 6.2 cm from point A and mark the endpoint as C on the line segment. This will be the vertex opposite the right angle.
3. Now, with point C as the center, draw an arc with a radius of 4.8 cm. This arc will intersect the line segment at two points. Mark one of these points as B.
4. Join the points A and B to complete the triangle ABC.
Note: In a right-angled triangle, the base is referred to as the side opposite the right angle (BC), and the hypotenuse is the longest side (AC). Angle B, which is the right angle, will always measure 90°.
Construct a right triangle ABC in which base BC 4.8 Angle B 90 degree and ac 6.2
you can construct a right angle by making a perpendicular bisector of a line segment. That's one of the very first constructions you did.
Mark the right angle as point B.
Then, mark off side BA.
Then from A, set the radius to 6.2cm and draw an arc that intersects the perpendicular side to BA. The intersection is point C.