math

Tony had an equal number cranberry bars and walnut bars. He gave away 66 cranberry bars. He then had 4 times as many walnut bars as cranberry bars left. How many bars did he have at first?

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  1. Let:
    x= # of Cranberry Bars
    y= # of Walnut Bars

    x=4y-66

    The problem states that there are equal # of cranberry bars to walnut bars. So, y=x

    x=4x-66

    Solve for x will give you 22 (which is the number of cranberry bars+walnut bars Tony had after he gave away 66)

    So 22+66 = 88 bars

    Solve for x
    x= -22

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  2. This problem does not answer the actual question, "How many bars did he have at first?"

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  3. This solution does not answer the actual question, "How many bars did he have at first?" Shouldn't it also include the total of CB+WB?

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  4. if it takes that much effort than ill get my but out of here. i got this question for 5th grade like why x and y and 4x and WHATEVER why does math have to be like this.

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  5. How did you get 22

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