# math

Tony had an equal number cranberry bars and walnut bars. He gave away 66 cranberry bars. He then had 4 times as many walnut bars as cranberry bars left. How many bars did he have at first?

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1. Let:
x= # of Cranberry Bars
y= # of Walnut Bars

x=4y-66

The problem states that there are equal # of cranberry bars to walnut bars. So, y=x

x=4x-66

Solve for x will give you 22 (which is the number of cranberry bars+walnut bars Tony had after he gave away 66)

So 22+66 = 88 bars

Solve for x
x= -22

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2. This problem does not answer the actual question, "How many bars did he have at first?"

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3. This solution does not answer the actual question, "How many bars did he have at first?" Shouldn't it also include the total of CB+WB?

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4. if it takes that much effort than ill get my but out of here. i got this question for 5th grade like why x and y and 4x and WHATEVER why does math have to be like this.

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5. How did you get 22

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