A car accelerates uniformly in a straight line
from rest at the rate of 3.9 m/s2
.
What is the speed of the car after it has
traveled 56 m?
Answer in units of m/s.
vi = 0 m/s
a = 3.9 m/s^2
d = 56m
vf^2 = vi^2 +2a*d
vf^2 = 0 + 2(3.9*56)
vf^2 = 436.8 m/s
vf = 20.8997 m/s
=21 m/s
This is the speed of the car after it has traveled 56m.
To find the speed of the car after it has traveled 56 m, we can use the kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity/speed
u = initial velocity/speed (in this case, the car starts from rest, so u = 0 m/s)
a = acceleration
s = displacement
Given that the car accelerates uniformly at a rate of 3.9 m/s^2 and has traveled 56 m, we can substitute these values into the equation:
v^2 = 0 + 2(3.9)(56)
v^2 = 0 + 2(218.4)
v^2 = 0 + 436.8
v^2 = 436.8
To find v (the speed), we take the square root of both sides of the equation:
v = √436.8
Calculating this, we find:
v ≈ 20.9 m/s
Therefore, the speed of the car after it has traveled 56 m is approximately 20.9 m/s.