balance Redox :- CuS + SO4²- = CuO+SO2
CuS + 6H^+ + 3SO4²- = CuO + 4SO2 + 3H2O
Well, it seems like we've got ourselves a balancing act here. Let's bring out the balancing sticks and get to work!
First, let's take a look at sulfur (S). It starts as -1 in sulfate (SO4²-) and ends up as +4 in sulfur dioxide (SO2). That means it gained some weight!
Now let's move on to copper (Cu). It starts as +2 in copper sulfide (CuS) and ends up as +2 in copper oxide (CuO). No big changes for our copper friend.
Let's start by balancing the sulfur (S). Since it gained weight, we need to add some more SO4²- ions. Let's add 4 SO4²- on the left side to balance out the sulfur atoms.
CuS + 4SO4²- =
Now, let's tackle the charge imbalance. On the left side, we have a total charge of -2 (2- from CuS). On the right side, we have a total charge of -6 (4- from SO4²- and 2+ from CuO).
To balance out the charges, we'll add 4 CuO on the right side, giving us:
CuS + 4SO4²- = 4CuO
And voila! Our redox equation is now balanced with equal atoms and equal charges on both sides. Mission accomplished!
Just remember, balancing equations is like juggling -- it takes practice, but you'll get there!
To balance the given redox reaction:
Step 1: Assign oxidation states to each element in the reaction.
CuS + SO4²- = CuO + SO2
The oxidation states of Cu, S, O, and S are:
Cu: unknown
S: -2 (in SO4²-) and unknown (in CuS)
O: -2 (in SO4²-) and unknown (in CuO)
Step 2: Identify the elements undergoing oxidation and reduction.
In this case, Cu is undergoing oxidation, and S and O are undergoing reduction.
Step 3: Balance the elements undergoing oxidation and reduction.
First, balance the reduction half-reaction:
CuS → CuO
To balance the sulfur (S) atoms, add 3 to the product side:
CuS → CuO + 3
Next, balance the oxidation half-reaction:
SO4²- → SO2
To balance the oxygen (O) atoms, add 2 to the reactant side:
SO4²- + 2 → SO2
Step 4: Balance the charge by adding electrons.
The total charge on the left side is -2 (from SO4²-), and the total charge on the right side is 0.
To balance the charges, add 4 electrons (4e-) to the left side:
SO4²- + 2 + 4e- → SO2
Step 5: Balance the electrons between the two half-reactions.
Multiply the oxidation half-reaction by 4 and the reduction half-reaction by 2 to equalize the number of electrons in both reactions:
4(SO4²- + 2 + 4e- → SO2)
2(CuS → CuO + 3)
This gives us:
4SO4²- + 8 + 16e- → 4SO2
2CuS → 2CuO + 6
Step 6: Combine the two half-reactions.
To combine the half-reactions, multiply the first reduction half-reaction by 4 and the second oxidation half-reaction by 1:
4(SO4²- + 2 + 4e- → SO2)
2(CuS → CuO + 3)
This gives us the balanced redox equation:
4SO4²- + 8 + 16e- + 2CuS → 4SO2 + 2CuO + 6
To balance the given redox equation: CuS + SO4^2- = CuO + SO2, we need to follow a few steps.
Step 1: Identify the oxidation states of each species in the equation.
The oxidation state of Cu in CuS is +2, S in CuS is -2, O in CuO is -2, and S in SO4^2- is +6. The oxidation state of oxygen is usually -2, and since there are two oxygen atoms in SO4^2-, the overall charge is -2.
CuS: Cu (+2) and S (-2)
SO4^2-: S (+6) and O (-2)
Step 2: Determine the changes in oxidation states for each species in the equation.
Cu is going from +2 to 0 (reduction), S is going from -2 to +4 (oxidation), O is going from -2 to 0 (reduction), and S is going from +6 to +4 (reduction).
Step 3: Balance the atoms that are undergoing the changes in oxidation states.
To balance the sulfur atom, we need to add an extra S atom to the product side of the equation:
CuS + SO4^2- = CuO + SO2 + S
Step 4: Balance the charges by adding electrons.
Since sulfur is going from a higher to a lower oxidation state, it is gaining electrons. So, we need to add 2 electrons to the product side to balance the charge:
CuS + SO4^2- = CuO + SO2 + S + 2e-
Step 5: Balance the electrons.
Now we need to balance the electrons transferred by multiplying each half-reaction by a factor to equalize the number of electrons. In this case, we have 2 electrons in one half-reaction and none in the other, so we multiply the first half-reaction by 2:
2CuS + 2SO4^2- = 2CuO + 2SO2 + 2S + 4e-
Step 6: Make sure the number of atoms is balanced on both sides.
Count the atoms on both sides of the equation and adjust the coefficients as needed to balance them:
2CuS + 2SO4^2- = 2CuO + 2SO2 + 2S + 4e-
The balanced redox equation is:
2CuS + 2SO4^2- = 2CuO + 2SO2 + 2S + 4e-