Two ropes are pulling upward on a large crate. The weight of the crate is 458 N. The tension in the left rope is the same as the tension in the right rope.If the crate is accelerating upward at a rate of 1.95 m/s2, and the tension in the two ropes is the same, what is the tension in the left rope?
how bout you just give me the answer
the weight is evenly distributed so half of the N per rope.
undo the weight which is massx9.80 by taking the mass divided by 9.80 then add acceleration to the acceleration of the earths gravity (fg=9.80) so that it looks like this; mass x (fg + a) then devide in two so each rope has the new adjusted force of tension on it.
To find the tension in the left rope, we need to use Newton's second law of motion.
According to Newton's second law, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the mass of the crate is not given, but we can find it using the weight of the crate.
The weight of the crate is given as 458 N. The weight of an object is equal to its mass multiplied by the acceleration due to gravity. The acceleration due to gravity on Earth is approximately 9.8 m/s^2.
Therefore, we can find the mass of the crate by dividing the weight by the acceleration due to gravity:
mass = weight / acceleration due to gravity
mass = 458 N / 9.8 m/s^2
mass ≈ 46.73 kg
Now that we have the mass of the crate, we can find the tension in the ropes using the equation:
net force = mass * acceleration.
Since the crate is accelerating upward, the net force is equal to the tension in the ropes minus the weight of the crate:
net force = tension - weight.
We can rearrange this equation to solve for the tension:
tension = net force + weight.
Substituting in the known values, we have:
tension = mass * acceleration + weight
tension = 46.73 kg * 1.95 m/s^2 + 458 N
tension ≈ 91.05 N.
Therefore, the tension in the left rope is approximately 91.05 N.