You roll two fair dice. Let E be the event that an even total shows on the dice. Let F be the event that a three shows on at least one die. Find P(F) and P(F∣E).

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  1. p(f)=1/6*5/6 + 1/6*5/6 + 1/6*1/6

    if a 3 shows on one die, then to be even sum, the other die has to be odd.
    P(fgivenE)=1/6*3/6+3/6*1/6 only two ways.

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