A transformer has 60 turns in the primary and 1200 turns in secondary.if the primary voltage is 500 V what will be the secondary voltage be? What will the current be if the primary if the secondary carries 2.0 A

Kindly show the solution plsss:)

300 c

To find the secondary voltage of the transformer, you can use the turns ratio formula:

Primary turns / Secondary turns = Primary voltage / Secondary voltage

Given that the transformer has 60 turns in the primary and 1200 turns in the secondary, and the primary voltage is 500 V, we can substitute these values into the formula:

60 / 1200 = 500 / Secondary voltage

Now, you can solve for the secondary voltage:

(60 * Secondary voltage) = (1200 * 500)
Secondary voltage = (1200 * 500) / 60

Secondary voltage = 10000 V

So, the secondary voltage will be 10,000 V.

To find the current in the primary if the secondary carries 2.0 A, you can use the transformer equation:

Primary current / Secondary current = Secondary turns / Primary turns

Given that the secondary current is 2.0 A, and the turns ratio is 1200/60, you can substitute these values in the equation:

Primary current / 2.0 A = 60 / 1200

Now, you can solve for the primary current:

Primary current = (2.0 A * 60) / 1200

Primary current = 0.1 A

So, the current in the primary will be 0.1 A.

To calculate the secondary voltage, you can use the turns ratio formula, which states that the ratio of the number of turns in the primary coil (N₁) to the number of turns in the secondary coil (N₂) is equal to the ratio of the primary voltage (V₁) to the secondary voltage (V₂).

So, the formula can be written as:

N₁/N₂ = V₁/V₂

In this case, the primary coil has 60 turns (N₁), the secondary coil has 1200 turns (N₂), and the primary voltage (V₁) is 500 V. Let's determine the secondary voltage (V₂):

60/1200 = 500/V₂

To find V₂, we can cross-multiply and solve for V₂:

60V₂ = 1200 * 500
V₂ = (1200 * 500)/60
V₂ = 10,000 V

Therefore, the secondary voltage would be 10,000 V.

To calculate the current in the primary if the secondary carries 2.0 A, you can use the current ratio formula. The formula states that the ratio of the primary current (I₁) to the secondary current (I₂) is equal to the inverse of the turns ratio (N₂/N₁):

I₁/I₂ = N₂/N₁

In this case, the turns ratio is 1200/60 or 20. The secondary current (I₂) is given as 2.0 A. Let's determine the primary current (I₁):

I₁/2.0 = 20/1

To find I₁, we can cross-multiply and solve for I₁:

I₁ = 2.0 * 20
I₁ = 40 A

Therefore, the current in the primary would be 40 A.