How many grams of CO2 is produced from 855 grams of C6H12O6 in the process of cell respiration?
C6H12O6 + 6O2 ==> 6CO2 + 6H2O
mols C6H12O6 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols C6H12O6 to mols CO2.
Then grams CO2 = mols CO2 x molar mass CO2.
What do I do to convert the mols of C6H12O6 to mols CO2 , I can't understand how I will use the coefficients???
(855/180)mols C6H12O6 x (6 mols CO2/1 mol C6H12O6) = (855/180) mols C6H12O6 x (6/1 = ?mols CO2
To determine the number of grams of CO2 produced from 855 grams of C6H12O6 in the process of cell respiration, we need to follow a few steps:
Step 1: Convert the mass of C6H12O6 to the number of moles.
The molar mass of C6H12O6 can be calculated by adding the atomic masses of carbon (C), hydrogen (H), and oxygen (O):
C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol
Molar mass of C6H12O6 = (6 * 12.01) + (12 * 1.01) + (6 * 16.00) = 180.18 g/mol
To convert the mass of C6H12O6 to moles, we divide the given mass by the molar mass:
Number of moles = Mass / Molar mass = 855 g / 180.18 g/mol
Step 2: Determine the stoichiometry of CO2 production.
The balanced equation for cell respiration is:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
From the equation, we can see that for every 1 mole of C6H12O6 consumed, 6 moles of CO2 are produced.
Step 3: Calculate the number of moles of CO2 produced.
By using the stoichiometry of the balanced equation, we can directly relate the number of moles of C6H12O6 to the number of moles of CO2:
Moles of CO2 produced = Moles of C6H12O6 * (6 moles of CO2 / 1 mole of C6H12O6)
Step 4: Convert the number of moles of CO2 to grams.
To convert moles to grams, we need to multiply the number of moles by the molar mass of CO2. The molar mass of CO2 is calculated by adding the atomic masses of carbon and oxygen:
C: 12.01 g/mol
O: 16.00 g/mol
Molar mass of CO2 = 12.01 + (2 * 16.00) = 44.01 g/mol
Grams of CO2 produced = Moles of CO2 * Molar mass of CO2
Following these steps, we can now calculate the grams of CO2 produced from 855 grams of C6H12O6.