1 / (x - 1) at x = 2
What is the slope of the curve?
Find the derivative of y = 1/(x-1)
Rewrite y = 1/(x-1) as y = (x-1)^-1
We can now use the power and chain rule.
dy/dx = -(x-1)^-2 times 1 (times 1 because you have to multiply by the derivative of the inside function
dy/dx = -1/(x-1)^2
Now, plug x = 2 into the dy/dx
dy/dx = -1/(2-1)^2 = -1/1
-1 is your slope at x = 2.