Ms. Kork sold her car for $8700. This was $100 more than 2/5 of what she paid for the car originally. How much had ms. Kork paid for the car??
cost price --- x
selling price = (2/5)x+100
(2/5)x + 100 = 8700
times 5
2x + 500 = 43500
2x = 43000
x = 21,500
check:
(2/5)(21500) = 8600
which differs from her selling price by $100
Let's assume the original price Ms. Kork paid for the car is "x".
According to the problem statement, Ms. Kork sold the car for $8700, which is $100 more than 2/5 of the original price.
We can set up an equation to represent this information:
8700 = (2/5) * x + 100
First, let's isolate the term (2/5) * x on one side of the equation:
(2/5) * x = 8700 - 100
(2/5) * x = 8600
Now, let's solve for x by multiplying both sides of the equation by 5/2:
x = (8600) * (5/2)
x = 43000/2
x = 21500
Therefore, Ms. Kork paid $21500 for the car originally.
To find out how much Ms. Kork originally paid for the car, we'll use algebra.
Let's use the variable "x" to represent the original price of the car. According to the information given, Ms. Kork sold the car for $8700, which was $100 more than 2/5 of the original price.
So, we can write the equation:
8700 = (2/5)x + 100
First, let's subtract 100 from both sides of the equation:
8700 - 100 = (2/5)x
8600 = (2/5)x
To get rid of the fraction, multiply both sides of the equation by 5/2:
(5/2) * 8600 = x
Now, let's evaluate the left side of the equation:
(5/2) * 8600 = 21500
Therefore, Ms. Kork originally paid $21500 for the car.