Betsy is making a flag. She can choose three colors from red, white, blue, & yellow. How many choices does Betty have?
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Choices= 4!/(3!*1!)=4
To find the number of choices Betsy has, we can use the concept of combination.
Since Betsy can choose three colors from four options, we can use the formula for combinations:
nCr = n! / (r! * (n-r)!)
Where n is the total number of options and r is the number of choices.
In this case, n = 4 (red, white, blue, yellow) and r = 3 (Betsy can choose three colors).
Plugging these values into the formula, we get:
4C3 = 4! / (3! * (4-3)!)
Calculating:
4C3 = 4! / (3! * 1!)
To simplify, let's compute the factorials:
4! = 4 * 3 * 2 * 1 = 24
3! = 3 * 2 * 1 = 6
1! = 1
Now substitute these values back into the formula:
4C3 = 24 / (6 * 1)
Calculating:
4C3 = 24 / 6
4C3 = 4
Therefore, Betsy has 4 choices when selecting three colors from red, white, blue, and yellow.
To determine the number of choices Betsy has, we need to consider that she can choose three colors from a set of four colors: red, white, blue, and yellow.
To find the number of choices, we can use the concept of combinations, specifically the formula for calculating combinations.
The formula for calculating combinations is:
nCk = n! / (k! * (n-k)!)
Where n represents the total number of items to choose from, and k represents the number of items to choose.
In this case, n = 4 (the total number of colors available), and k = 3 (the number of colors Betsy can choose).
Plugging the values into the formula, we get:
4C3 = 4! / (3! * (4-3)!)
= 4! / (3! * 1!)
= (4 * 3 * 2 * 1) / (3 * 2 * 1 * 1)
= 24 / 6
= 4
Therefore, Betsy has 4 choices for her flag.