A hemispherical bowl of radius 6cm contains water which is flowing into it at a constant rate.When the height of the water is h cm the volume V of water in the bowl is given by V=22/7(6h^2-1/3h^3)cm^3.Find the rate at which the water level is rising when h=3,given that the time taken to fill the bowl is 1minute.
Why can't you just put the subject in the subject box? Otherwise, the right folks will never look at it.
dV/dt=PI(12h - h^2)dh/dt
solve for dh/dt when h=3, and
v(h=6)=dv/dt * 60 sec or
dv/dt=PI (6*6^2-1/3 *6^3)/30 in cm^3/secposted by bobpursley