pope john
A hemispherical bowl of radius 6cm contains water which is flowing into it at a constant rate.When the height of the water is h cm the volume V of water in the bowl is given by V=22/7(6h^21/3h^3)cm^3.Find the rate at which the water level is rising when h=3,given that the time taken to fill the bowl is 1minute.
dV/dh=22/7
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Why can't you just put the subject in the subject box? Otherwise, the right folks will never look at it.
VV=PI(6h^21/3h^3)
dV/dt=PI(12h  h^2)dh/dt
solve for dh/dt when h=3, and
v(h=6)=dv/dt * 60 sec or
dv/dt=PI (6*6^21/3 *6^3)/30 in cm^3/secposted by bobpursley
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