I am an odd number . The sum of my digit is 10. The number is my hundreds is one less than tens . The number of my ones is 3 more than my hundreds. The difference between the number of my ones and the number of my tens is 2 way number am I
Assume a three digit number
ABC, and C is an odd digit.
A+B+C=10
A= B-1
C-B=2 or C=B+2
then
B-1+B+B+2=10
3B=9
B=3
A=2
C=5
ABC is 235
371
To find the answer to this question, let's go through the given information step by step:
1. The sum of the digits is 10.
This means that the three digits of the number add up to 10.
2. The number in the hundreds place is one less than the number in the tens place.
Let's call the number in the hundreds place "H" and the number in the tens place "T". So we have the equation H = T - 1.
3. The number in the ones place is 3 more than the number in the hundreds place.
Let's call the number in the ones place "O". So we have the equation O = H + 3.
4. The difference between the number in the ones place and the number in the tens place is 2.
This gives us the equation O - T = 2.
Now, let's solve these equations to find the values of H, T, and O.
From equation 2, we can substitute H = T - 1 into equation 3:
O = (T - 1) + 3
O = T + 2
Substituting this value of O into equation 4:
(T + 2) - T = 2
2 = 2
This equation is not true, which means there is no solution that satisfies all the given conditions. Therefore, there is no number that meets all the given conditions.