How many grams of sodium bicarbonate (NaHCO3) are needed to make a 0.6M solution?
depends on how much solution you want. For 1L, you will need 0.6 moles of NaHCO3.
So, figure the wol wt (grams) and take .6 times that
To determine the number of grams of sodium bicarbonate (NaHCO3) needed to make a 0.6M solution, we will need to know the volume of the solution you want to prepare. The molarity (M) is a measure of the number of moles of solute (in this case, NaHCO3) per liter of solution.
1. Start by determining the number of moles of NaHCO3 needed. This can be done using the formula:
Moles = Molarity (M) × Volume (L)
2. Rearrange the equation to solve for moles:
Moles = 0.6 M × Volume (L)
3. Since we want to find the grams of NaHCO3 required, use the molar mass of NaHCO3 (22.99 g/mol for sodium, 1.01 g/mol for hydrogen, 12.01 g/mol for carbon, and 16.00 g/mol for oxygen) to convert the moles to grams:
Grams = Moles × Molar mass (g/mol)
By inputting your desired volume for the solution, you should be able to calculate the number of grams of NaHCO3 needed.