For three consecutive odd​ integers, the sum of 3 times the first integer and 2 times the second integer is 7 less than 4 times the third integer. What are the three​ integers?

Separate your answers with commas.​ Ex: 1,2,3

Please show work thank you

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To solve this problem, let's represent the three consecutive odd integers as x, x + 2, and x + 4.

According to the problem, the sum of 3 times the first integer and 2 times the second integer is 7 less than 4 times the third integer. Mathematically, this can be expressed as:

3x + 2(x + 2) = 4(x + 4) - 7

Now, let's solve the equation step by step:

3x + 2x + 4 = 4x + 16 - 7

Combine like terms:

5x + 4 = 4x + 9

Subtract 4x from both sides:

5x - 4x + 4 = 9

Simplify:

x + 4 = 9

Subtract 4 from both sides:

x = 9 - 4

x = 5

Now that we have the value of x, we can substitute it back into the original expression to find the other two integers:

The three integers are: 5, 7, 9

So, the solution is 5, 7, 9.