Physics

A ball thrown horizontally at 21m/s from the roof of a building lands 24m from the base of the building. Now high is the building?

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  1. Refer to these equations.

    Vx (Horizontal velocity) (21m/s here)
    Vx = dx/t
    Dx (Horizontal distance) (24m here)
    Dx = vx(t)
    Dy (Vertical distance) (missing here)
    dy=(1/2)(g)t^2

    t is just time.
    you can use first or second equation to find time. either one works.
    21m/s = 24m / t
    t = 24/21 = 1.14 seconds

    Now put time value to last equation
    dy = (1/2)(9.8)1.14^2

    dy = 6.36804 or 6.37m

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