the sum of1st 6 term of an Ap is 6.The product of second and fifth term is-80find the terms of Ap
6a + 5d = 6
... a = 1 - 5d/6
(2a + d) (5a + 4d) = -80
... 10 a^2 + 13 ad + 4 d^2 = -80
substitute for the value of a
solve for d
substitute back to find a