A fair coin is tossed six times. Find the probability of getting head, head, head, head, tail, tail in that order
the probability of getting any six specific tosses is (1/2)^6
To find the probability of getting a specific sequence of outcomes when tossing a fair coin multiple times, we need to calculate the probability of each individual outcome and then multiply them together.
In this case, we want to find the probability of getting "head, head, head, head, tail, tail" in that order.
Since each coin toss is independent and has two equally likely outcomes (heads or tails), the probability of getting heads on a single toss is 1/2 and the probability of getting tails is also 1/2.
To calculate the probability of a specific sequence, we multiply the probabilities of each individual outcome. Since we have six coin tosses, the probability of getting "head, head, head, head, tail, tail" in that order is:
(1/2) * (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/64.
Therefore, the probability of getting the sequence "head, head, head, head, tail, tail" in that order when tossing a fair coin six times is 1/64.