A, B, C, and D are 4 salts whose Ksp values are 9.21 × 10-8, 7.44 × 10-11, 1.07 × 10-21, and 38.65, respectively. What is the correct arrangement of their solubilities in decreasing order?
A. D, A, B, C
B. C, B, A, D
C. A, B, D, C
D. C, B, D, A
The answer is A!! According to APEX
To determine the correct arrangement of the solubilities of the salts A, B, C, and D in decreasing order, we need to compare their solubility product constants (Ksp) values.
The solubility of a salt is determined by its Ksp value, which is a measure of how soluble it is in water. Higher Ksp values indicate greater solubility.
Given the Ksp values:
- A: 9.21 × 10-8
- B: 7.44 × 10-11
- C: 1.07 × 10-21
- D: 38.65
Let's arrange them in decreasing order:
D (Ksp = 38.65) > A (Ksp = 9.21 × 10-8) > B (Ksp = 7.44 × 10-11) > C (Ksp = 1.07 × 10-21)
Therefore, the correct arrangement of their solubilities in decreasing order is:
C. A, B, D, C
To determine the correct arrangement of solubilities in decreasing order, we need to compare the Ksp values of the salts.
The Ksp value represents the solubility product constant, which is a measure of the solubility of a compound in water. The higher the Ksp value, the more soluble the compound is.
Comparing the Ksp values given for salts A, B, C, and D, we can sort them in descending order to find the correct arrangement of solubilities:
Salt D has the highest Ksp value of 38.65.
Salt A has a Ksp value of 9.21 × 10^-8.
Salt B has a Ksp value of 7.44 × 10^-11.
Salt C has the lowest Ksp value of 1.07 × 10^-21.
Therefore, the correct arrangement of solubilities in decreasing order is:
C. A, B, D, C