A tank is drained by two pipes.One pipe can empty the tank in 30minutes,and the can empty it in 25minutes.If the tank is 5/6 filled and both pipes are opened,in what time will the tank be emptied
1/30 + 1/25 = (5/6)/x
LCD is 150
[1/30 + 1/25 = (5/6)/x] 150
5+6 = 125/p
11p = 125
11p/11 = 125/11
p = 125/11 ~ 11.3636
Please explain it further
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Answer 11.3636
To solve this problem, we need to determine the combined rate at which the two pipes empty the tank.
Let's find the individual rates at which each pipe empties the tank:
- The first pipe can empty the tank in 30 minutes, so its rate is 1/30 tanks per minute.
- The second pipe can empty the tank in 25 minutes, so its rate is 1/25 tanks per minute.
To find the combined rate, we add up the rates of both pipes:
Combined rate = 1/30 + 1/25 = 5/150 + 6/150 = 11/150 tanks per minute.
Since the tank is 5/6 filled, this means it has 1 - 5/6 = 1/6 of its volume to be emptied.
To find out how long it takes for the tank to be emptied, we divide the remaining volume of the tank by the combined rate:
Time = (1/6) / (11/150)
= (1/6) * (150/11)
= 25/11 minutes.
Therefore, if both pipes are opened, the tank will be emptied in approximately 2.27 minutes or 2 minutes and 16.36 seconds.