How many total moles of ions are released when each of the following samples dissolves completely in water? ?

3.70g of CuSO4 5H2O

CuSO4.5H2O ==> Cu^+2 + SO4^- + 5H2O

Convert 3.70 g CuSO4.5H2O to mols CuSO4.5H2O. Then for each mol of the starting material, you obtain 1 mol Cu^+2 ions and 1 mol SO4^-2 ions. Add those together to find the total mols. I've not added the H2O since that doesn't ionize (at least not that much).

Well, it seems like you're in a tricky situation. Let's see if we can solve it with a bit of humor!

If you want to find out how many moles of ions are released when 3.70g of CuSO4 · 5H2O dissolves completely in water, you first need to determine the molar mass of the compound.

The molar mass of CuSO4 · 5H2O can be calculated as follows:

1 atom of Cu (63.55 g/mol) + 1 atom of S (32.07 g/mol) + 4 atoms of O (4 x 16.00 g/mol) + 5 molecules of H2O (5 x 18.02 g/mol)

So, add all those up and you get the molar mass of CuSO4 · 5H2O. But remember, we're doing this with humor, so let's turn it into a joke!

Why was the molar mass of CuSO4 · 5H2O feeling lonely?

Because it needed some friends (the atoms) to hang out with!

Now that we know the molar mass of CuSO4 · 5H2O (which is approximately 249.68 g/mol), we can use it to determine the number of moles of the compound in 3.70g.

So, take the given mass of CuSO4 · 5H2O (3.70g) and divide it by the molar mass (249.68 g/mol). This will give you the number of moles of CuSO4 · 5H2O.

But remember, I'm here to lighten the mood, so here's another joke for you:

Why did the mole go to therapy?

Because he had separation anxiety from his atoms!

Now, back to the calculations. Once you have found the number of moles of CuSO4 · 5H2O, you can use the coefficients in the chemical formula to determine the number of moles of ions released.

For each formula unit of CuSO4, one mole of Cu^2+ ions and one mole of SO4^2- ions are released. So, the total number of moles of ions released would be twice the number of moles of CuSO4.

But before we proceed, let me share another joke with you:

Why don't chemistry jokes always work?

Because all the good ones Argon!

So, let's calculate the number of moles of ions released by multiplying the moles of CuSO4 · 5H2O by 2.

I hope this explanation brought some smiles to your face!

To determine the total moles of ions released when a sample dissolves completely in water, you need to consider the number of ions present in the compound.

Let's start by calculating the molar mass of CuSO4 5H2O:

Molecular weight of CuSO4 = 63.55 g/mol (copper) + 32.07 g/mol (sulfur) + (4 x 16.00 g/mol) (oxygen) = 159.61 g/mol
Molecular weight of H2O = 2 (1.01 g/mol) + 16.00 g/mol = 18.02 g/mol

To determine the molar mass of the entire compound, we add the molar mass of CuSO4 to the molar mass of 5H2O:

Molar mass of CuSO4 5H2O = 159.61 g/mol + (5 x 18.02 g/mol) = 249.69 g/mol

Now, we can calculate the number of moles by dividing the mass of the sample by the molar mass:

Number of moles = mass (g) / molar mass (g/mol)
Number of moles = 3.70 g / 249.69 g/mol

Let's solve the equation:

Number of moles = 0.0148 mol

Since CuSO4 dissociates into Cu2+ and SO4 2- ions, the stoichiometry indicates that for each formula unit of CuSO4, one Cu2+ ion and one SO4 2- ion are released.

Therefore, the number of moles of ions released will be twice the number of moles of CuSO4:

Total moles of ions = 2 x 0.0148 mol = 0.0296 mol

Therefore, when 3.70 g of CuSO4 5H2O dissolves completely in water, a total of 0.0296 moles of ions are released.

To determine the total moles of ions released when a compound dissolves in water, we need to break down the compound into its constituent ions.

The formula for copper(II) sulfate pentahydrate, CuSO4 · 5H2O, tells us that for every one formula unit of the compound, we have one copper ion (Cu2+), one sulfate ion (SO42-), and five water molecules (H2O).

To find the number of moles of CuSO4 · 5H2O, we first need to find the molar mass of the compound. The molar mass is the sum of the atomic masses of all the atoms in one formula unit.

The atomic masses are:
- Cu: 63.55 g/mol
- S: 32.07 g/mol
- O: 16.00 g/mol (x4 for four oxygen atoms)
- H: 1.01 g/mol (x10 for ten hydrogen atoms)

Molar mass of CuSO4 · 5H2O = (63.55 g/mol) + (32.07 g/mol) + (16.00 g/mol x 4) + (1.01 g/mol x 2 x 5) = 249.69 g/mol

Next, we calculate the number of moles of CuSO4 · 5H2O using the mass of the sample given:

Number of moles = Mass of sample / Molar mass
Number of moles = 3.70 g / 249.69 g/mol

Calculating this division gives us the number of moles of CuSO4 · 5H2O.

Finally, since there is one copper ion (Cu2+) and one sulfate ion (SO42-) released per formula unit of CuSO4 · 5H2O, we can say the total moles of ions released is equal to the number of moles of CuSO4 · 5H2O.

Therefore, the total moles of ions released when 3.70 g of CuSO4 · 5H2O dissolves completely in water is equal to the number of moles of CuSO4 · 5H2O calculated using the formula above.