i kinda understand waht you're saying. to be a bit more clear this is from a lab,

and here are the volumes we retrieved:

Volume of Concentrated NaOH soultion (mL) = 9.00 mL

Concentration of Concentrated NaOH soultuon (M) = 6.00 M

Volume of Stock Solution after Dilution (mL) = 490.00 mL + 9.00 mL (from the first part)

and then the question says the give the Approximate concentration of Stock solution (M).

It says to use the formula: amount of solute (moles) / volume of solution (L)

I'm confused with how to get amount of solute with the 6.00 M and 9.00mL volume.

3 answers

Answered below.

yep just saw, thanks :)

To find the approximate concentration of the stock solution (M), we can use the formula provided:

Concentration (M) = amount of solute (moles) / volume of solution (L)

Given:
Volume of Concentrated NaOH solution (mL) = 9.00 mL
Concentration of Concentrated NaOH solution (M) = 6.00 M
Volume of Stock Solution after Dilution (mL) = 490.00 mL + 9.00 mL

To find the amount of solute in moles, we need to convert the volume of concentrated NaOH solution to liters:

9.00 mL x (1 L / 1000 mL) = 0.009 L

Next, we can calculate the amount of solute (moles) using the concentration and volume of the concentrated solution:

Amount of solute (moles) = concentration (M) x volume (L)

Amount of solute (moles) = 6.00 M x 0.009 L = 0.054 moles

Finally, we can determine the approximate concentration of the stock solution by dividing the amount of solute by the total volume of the solution after dilution:

Volume of Stock Solution after Dilution (L) = (490.00 mL + 9.00 mL) / 1000 mL

Volume of Stock Solution after Dilution (L) = 0.499 L

Approximate concentration of Stock Solution (M) = amount of solute (moles) / volume of solution (L)

Approximate concentration of Stock Solution (M) = 0.054 moles / 0.499 L

Approximate concentration of Stock Solution (M) = 0.108 M

Hence, the approximate concentration of the stock solution is 0.108 M.