Physics

If a basketball player has a vertical leap of 1.29 m , then what is his takeoff speed and his hang time ( total time to move upwards to the peak and then return to the ground ) ?

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  1. time rising: 4.9t^2 = 1.29
    double that for total hang time.

    v = 9.8t

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  2. Hello sir thank you for answering but I can't seem to find how we got the v ( velocity ) to be as 9.8 ... Isn't that the acceleration

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  3. distance: s = 1/2 at^2
    speed: v = at

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