The observation deck of tall skyscraper is 370. m above the time required for a penny to free fall from the deck to the street below and its velocity when it reaches the ground . Plzz help I know the t= .869 and the v= 85.2 and thank u :) have a good day plz answer this is a graded hw 😩

4.9t^2 = 370

v = 9.8t

To calculate the time required for a penny to free fall from the observation deck of a tall skyscraper to the street below, we can use the kinematic equation for free fall:

h = (1/2) * g * t^2

where:
h is the height (370 m),
g is the acceleration due to gravity (approximately 9.8 m/s^2),
and t is the time.

To find the time (t), we need to rearrange the equation and solve for t. Let's substitute the given values:

370 m = (1/2) * 9.8 m/s^2 * t^2

Simplifying the equation:

370 = 4.9t^2

Now, divide both sides by 4.9:

370 / 4.9 = t^2

Using a calculator:

t^2 β‰ˆ 75.51

To find t, we need to take the square root of both sides:

t β‰ˆ √75.51

Using a calculator:

t β‰ˆ 8.68 seconds (rounded to two decimal places)

Therefore, the time required for the penny to free fall from the observation deck to the street below is approximately 8.68 seconds (t β‰ˆ 8.68 s).

Now, let's calculate the velocity (v) of the penny when it reaches the ground. We can use another kinematic equation:

v = g * t

where:
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time (8.68 s)

Substituting the values:

v = 9.8 m/s^2 * 8.68 s

Using a calculator:

v β‰ˆ 85.2 m/s (rounded to one decimal place)

Therefore, the velocity of the penny when it reaches the ground is approximately 85.2 m/s (v β‰ˆ 85.2 m/s).