How much mL of dilute nitric acid is needed to add in control solution in chloride limit test in sodium hydroxide sample???can u please give me Answer urgently??

If this is a qual test you need have enough dil HNO3 to make the solution slightly acid. Add dil HNO3 to the solution dropwise until it is acid to litmus paper. The actual amount you need to add will be determined by the amount of NaOH present in the test.

No i have idea for sample solution for that i have to add 10 mL but i have a que for standard solution becoz i have to compare the tubidity of solution

Can u check it inwant answer according to japanese pharmacopia

Sorry, I know nothing about the Japanese pharmacopeia.

To determine the amount of mL of dilute nitric acid needed to add in the control solution for the chloride limit test in a sodium hydroxide sample, I will provide you with the general steps and explanation of the procedure. However, please note that the specific details of the test may depend on the method or protocol you are following. Typically, the chloride limit test is performed using silver nitrate as the precipitating agent. Here's how you can calculate the volume of nitric acid needed:

1. Prepare the control solution: Take a known volume (e.g., 50 mL) of sodium hydroxide sample in a glass beaker.

2. Add a few drops of phenolphthalein indicator to the sodium hydroxide solution. Phenolphthalein serves as an indicator to identify the endpoint of reaction.

3. Slowly titrate the sodium hydroxide solution with silver nitrate solution until a pinkish color appears. The silver nitrate reacts with chloride ions to form a white precipitate called silver chloride.

4. The formation of this pinkish color indicates that all the chloride ions have been precipitated. This is the endpoint of the reaction.

5. Once the endpoint is reached, note the volume of silver nitrate solution (in mL) that you have used.

6. Now, calculate the number of moles of chloride ions present in your sodium hydroxide sample using the following formula:

Moles of chloride ions = Volume of silver nitrate solution (in mL) × Molarity of silver nitrate solution

7. Based on the balanced equation of the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl), you can determine the stoichiometry of the reaction. It is typically 1:1.

For example, the balanced equation would be: AgNO3 + NaCl → AgCl + NaNO3

This means that 1 mole of silver nitrate reacts with 1 mole of chloride ions to form 1 mole of silver chloride.

8. From the number of moles of chloride ions, you can deduce the moles of nitric acid required; assuming nitric acid is utilized as a part of the control solution.

9. Using the concentration (molarity) of the dilute nitric acid and the number of moles required, calculate the volume of dilute nitric acid needed using the formula:

Volume (in mL) = (Moles of nitric acid required / Molarity of nitric acid) * 1000

Remember to adjust the calculations according to the specific details and concentrations mentioned in your experiment procedure. It's always important to refer to the method or protocol you are following for accurate results.