In college softball, the distance from the pitcher's mound to the batter is 43 feet.
Part A
If the ball leaves the bat at 105 mph , how much time elapses between the hit and the ball reaching the pitcher?
Express your answer to two significant figures and include the appropriate units.
105mi/h * 5,280Ft/mi * 1h/3600s = 154 Ft/s.
d = r*t = 43, 154*t = 43, t = ?.
To find the time it takes for the ball to reach the pitcher after being hit, we need to use the formula for time:
time = distance / speed
In this case, the distance is the distance from the pitcher's mound to the batter, which is given as 43 feet. The speed is the velocity of the ball leaving the bat, which is given as 105 mph.
First, we need to convert the velocity from mph to feet per hour since the distance is given in feet. To do this, we use the conversion factor of 1 mile = 5280 feet:
105 mph * 5280 feet/1 mile = 554,400 feet/hour
Now we can calculate the time it takes for the ball to reach the pitcher:
time = 43 feet / 554,400 feet/hour
Calculating this, we get:
time ≈ 7.76 × 10^-5 hours
To express this answer to two significant figures, we can round it to 7.8 × 10^-5 hours.
Now let's convert hours to a more commonly used unit of time, such as seconds. There are 3600 seconds in one hour, so:
7.8 × 10^-5 hours * 3600 seconds/ 1 hour ≈ 0.28 seconds
Therefore, the time it takes for the ball to reach the pitcher after being hit is approximately 0.28 seconds.