How many grams of nacl are required to completely neutralize 100 ml of 1M h2so4?
I believe you need to read and correct the question. Also let me point out that nacl and h2so4 don't mean anything to me. Find the caps key and use it.
Sjjakana
I don't know the answer please solve this
To determine the number of grams of NaCl required to completely neutralize 100 ml of 1M H2SO4, we need to consider the reaction between the two compounds.
The balanced equation for the reaction is:
2 NaCl + H2SO4 -> Na2SO4 + 2 HCl
From the equation, we can see that two molecules of NaCl react with one molecule of H2SO4 to produce one molecule of Na2SO4 and two molecules of HCl.
To find the number of moles of H2SO4 in 100 ml of 1M solution, we use the formula:
Moles = Concentration (M) x Volume (L)
Converting the volume to liters:
100 ml = 100/1000 L = 0.1 L
Now, calculating the moles of H2SO4:
Moles = 1M x 0.1 L = 0.1 moles
Since the stoichiometric ratio between H2SO4 and NaCl is 1:2, we need twice as many moles of NaCl to neutralize the H2SO4.
Therefore, the number of moles of NaCl required = 2 x 0.1 moles = 0.2 moles
To convert moles of NaCl to grams, we need to know the molar mass of NaCl, which is approximately 58.5 g/mol.
Now, using the formula:
Mass = Moles x Molar mass
Mass of NaCl = 0.2 moles x 58.5 g/mol = 11.7 grams
Therefore, approximately 11.7 grams of NaCl are required to completely neutralize 100 ml of 1M H2SO4.