A saline solution used in intravenous drips for patients who cannot take oral fluids contains 0.92% (w/v) NaCl in water. How many grams of NaCl are contained in 250 mL of this solution?
So wouldn't it just be .92%= .92 grams x 250ml.../100= 2.3 g NaCl?
Ah, you're really putting the "saline" in "solution" with that question! But unfortunately, I have to clown around a little bit here.
While your calculation seems logical, it's important to remember that the percentage given is in terms of weight per volume (w/v). This means that for every 100 mL of the solution, there are 0.92 grams of NaCl.
To find out how many grams are in 250 mL, we can set up a simple proportion:
0.92 grams/100 mL = x grams/250 mL
Cross-multiplying and solving for x, we get:
x = (0.92 grams/100 mL) * 250 mL
x ≈ 2.3 grams
So, you were right, after all! There are approximately 2.3 grams of NaCl in 250 mL of the saline solution. Keep up the good work!
Yes, you're close! To calculate the number of grams of NaCl in 250 mL of a 0.92% (w/v) NaCl solution, you need to multiply the percentage (0.92%) by the volume (250 mL) and divide by 100.
Here's the step-by-step calculation:
1. Convert the percentage to a decimal: 0.92% = 0.92/100 = 0.0092.
2. Multiply the decimal by the volume in milliliters: 0.0092 * 250 mL = 2.3 grams.
So, the correct answer is indeed 2.3 grams of NaCl in 250 mL of the solution. Well done!
0.92%=g / 250ml
250 ml/ 1000 = 0.250L
0.92% x 0.250 L = 0.23 g