a number is divided into two parts such that one part is 10 more than the other. if the two parts are in the ratio 5:3,find the number and the two parts?

40 = 25 + 15



and all multiples to it

To solve this problem, we can use algebraic equations.

Let's assume the number is represented by 'x'.

According to the given information, one part of the number is 10 more than the other part. So, we can represent one part as 'x', and the other part will be 'x - 10'.

The ratio between the two parts is given as 5:3. So, we can set up the equation:

(x - 10) / x = 3 / 5

To solve this equation, we can cross-multiply:

5(x - 10) = 3x

Simplifying the equation, we get:

5x - 50 = 3x

Subtracting 3x from both sides:

2x - 50 = 0

Adding 50 to both sides:

2x = 50

Dividing by 2:

x = 25

So, the number is 25.

To find the two parts, we substitute this value back into our expressions:

One part = x = 25

The other part = x - 10 = 25 - 10 = 15

Therefore, the number is 25, and the two parts are 25 and 15, respectively.