Confused, conflicting texts
when you are finding % error for density
formula: experienced value-accepted value/ accepted value ×100. Does the ×100 cancel out the percent sign?
EX; 7.28g/mL-6.54g/mL/6.54g/mL ×100. Is the answer 11.31 or 11.31%
The lab video did not multiply the 100, but everything else I see says11.31g/mL%
Thank you, lulu
a) How will increasing the concentration of CO shift the equilibrium?
Suppose we have 5 apples and 5 oranges. The FRACTION of apples is 5/10 = 0.5. To change to percent, it's the fraction x 100 so 0.5 x 100 = 50%. The 100 ADDS the percent sign.
% = [(exp-accepted)/acceted]*100. If you want to remove the 100, then the % answer changes to the fraction. The answer in your question is 11.31%.
To calculate the percent error for density, you would use the formula: (experienced value - accepted value) / accepted value × 100. The × 100 in the formula is used to convert the decimal value to a percentage.
Let's use the values you provided as an example:
Experienced value = 7.28 g/mL
Accepted value = 6.54 g/mL
To calculate the percent error, plug in these values into the formula:
Percent error = (7.28 g/mL - 6.54 g/mL) / 6.54 g/mL × 100
Simplifying the equation:
Percent error = 0.74 g/mL / 6.54 g/mL × 100
Percent error = 0.1131 × 100
Now, this is where the confusion arises. At this point, you have two options:
Option 1:
To find the answer as a decimal, you would calculate:
Percent error = 0.1131 × 100 = 11.31
Option 2:
If you want the answer in percentage form, you would calculate:
Percent error = 0.1131 × 100 = 11.31%
Both answers are valid and correct. The lab video you watched might have chosen to present the answer as a decimal (11.31) rather than as a percentage (11.31%).
So, in conclusion, if you want the answer as a decimal, it would be 11.31, and if you want it as a percentage, it would be 11.31%.