calculate the mass of silver deposited when a current of 3ampere is passed through a solution of a silver salt for 7minutes
To calculate the mass of silver deposited, we need to use Faraday's Law of Electrolysis. According to Faraday's Law, the mass of substance deposited during electrolysis is proportional to the amount of charge passed through the electrolyte.
The formula we will use is:
Mass = (Current × Time × Atomic Mass) / (Faraday's Constant × Charge on Ion)
Let's break down the given information and plug it into the formula:
Current = 3 Amperes
Time = 7 minutes = 7 × 60 seconds = 420 seconds
Now, we need a few constants:
Atomic Mass of Silver (Ag) = 107.8682 g/mol
Faraday's Constant (F) = 96,485 C/mol (charge/mol of electrons)
Charge on Ion (Ag+) = +1 (Since silver ions have a +1 charge)
Plugging in the values into the formula:
Mass = (3 A × 420 s × 107.8682 g/mol) / (96,485 C/mol × 1)
By calculating this expression, we can determine the mass of silver deposited.
coulombs = amperes x seconds
C = 3A x 7 min x 60 sec/min = ?
96,485 coulombs will deposit 107.9 g Ag. So
107.9 g Ag x (? C/96,500 C) = ?