# Algebra

Find 3 consecutive odd numbers such that the sum of 5 times the smaller number a twice the larger number is 33 more than six times the median number.

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1. I am going to call the middle number x, then the smaller is x-2, and the larger is x+2

Now just translate the English to Math:
the sum of ----> +
5 times the smaller ---> 5(x-2)
number a twice the larger ---> 2(x+2)

the sum of 5 times the smaller number a twice the larger number ---> 5(x-2)+2(x+2)
is ---> =
33 more than six times the median number --> 6x+33

5(x-2) + 2(x+2) = 6x + 33
5x-10+2x+4=6x+33
x = 39

the numbers are 37, 39, and 41

check:
5(37) + 2(41) = 267
6(39) + 33 = 267

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