A boy spends 32% of his money and has 34 naira left . calculate how much he had at first
To find out how much the boy had at first, we can set up an equation using the information given.
Let's say the amount of money the boy had at first is x naira.
According to the information given, the boy spent 32% of his money, which means he has 68% of his money left. So, we can set up the equation:
0.68x = 34
To solve for x, we divide both sides of the equation by 0.68:
x = 34 / 0.68
Dividing 34 by 0.68 gives:
x = 50
Therefore, the boy had 50 naira at first.
To calculate how much money the boy had at first, we need to use a simple equation.
Let's assume the amount of money the boy had at first is 'x' naira.
If the boy spent 32% of his money, he would have 100% - 32% = 68% of his money left.
We can represent this as an equation: 68% of x = 34 naira.
To solve for x, first, let's convert 68% to a decimal by dividing it by 100: 68 / 100 = 0.68.
Now, we can rewrite the equation as: 0.68 * x = 34.
To isolate x, we can divide both sides of the equation by 0.68: x = 34 / 0.68.
Now let's calculate the value of x:
x = 34 / 0.68 = 50 naira.
Therefore, the boy had 50 naira at first.
0.68n = 34
n = 50