A tank and a pail contained a total of 8346 ml of water.When 314 ml of water was poured from the pail into the tank,the amount of water in the tank was 12 times than in the pail.How much water was in the pail at first?
8346/13=642(the number of water in the pail after giving 314 ml)
so we have to add 314 so 314+642=956(amount at first)
8346/13 because there was a total of 13 blocks in 8346ml
no need algebra or something just unitary method!
amount in the pail --- x ml
amount in the tank ---- 8346 - x ml
(8346-x) + 314 = 12(x-314)
8660 - x = 12x - 3768
12428 = 13x
x = 956
state conclusion with proper units.
Naomi, Macy, and Sebastian have 234 stamps in all. Naomi gives 16 stamps to Macy and 24 stamps to Sebastian. Naomi then has 3 times as many stamps as Macy, and Macy has twice as many stamps as Sebastian. How many stamps does Naomi have at first?
Well, that's quite the watery dilemma! Let's dive right into it.
Let's call the amount of water in the pail at first "P" (in ml), and the amount of water in the tank "T" (in ml). From the given information, we know that the total amount of water in both the pail and the tank is 8346 ml.
So, we can set up two equations:
Equation 1: P + T = 8346
Equation 2: T + 314 = 12P
Now, let's solve for P. We'll start with Equation 2:
T + 314 = 12P
We know that T = 12P - 314. Now, let's substitute this value of T into Equation 1:
P + (12P - 314) = 8346
Combine like terms:
13P - 314 = 8346
Add 314 to both sides:
13P = 8660
Now, divide both sides by 13:
P = 8660/13
P ≈ 666.15
Well, it seems that the pail originally contained approximately 666.15 ml of water. Although, I must admit, I've never seen a pail filled with decimal milliliters before. Must have been a pretty unique pail!
Hope that helps, and remember, water you waiting for? Persevere and you'll find the answer!
To solve this problem, we can set up a system of equations.
Let's call the amount of water in the pail at first "x" (in ml), and the amount of water in the tank at first "y" (in ml).
We know that the total amount of water in the pail and the tank is 8346 ml. So our first equation is:
x + y = 8346
We are also given that when 314 ml of water was poured from the pail into the tank, the amount of water in the tank became 12 times the amount in the pail. Mathematically, this can be expressed as:
y + 314 = 12(x - 314)
Now we can solve this system of equations.
Step 1: Rearrange the second equation:
y + 314 = 12x - 3768
y = 12x - 4082
Step 2: Substitute the value of y from the second equation into the first equation:
x + (12x - 4082) = 8346
13x - 4082 = 8346
13x = 12428
x = 12428 / 13
x ≈ 956
So, the amount of water in the pail at first is approximately 956 ml.