An object travels 8 m in the 1st second of travel, 8 m again in the 2nd second of travel, and 8 m again during the 3rd second of travel. its acceleration in meters per second per second is?

Would the answer to this question be 0?

I'm not positive, but wouldn't the acceleration be 8 m/s?

zero. It is going constant speed.

To determine the acceleration of an object, we need to calculate the change in velocity per unit of time. In this case, the object is traveling a distance of 8 meters in each second of travel.

The formula for acceleration is a = Δv / Δt, where a represents acceleration, Δv represents the change in velocity, and Δt represents the change in time.

Since the object is traveling 8 meters per second consistently and not changing its velocity, the change in velocity is 0. Therefore, Δv = 0.

Additionally, the time interval for each second of travel is Δt = 1 second.

Now, let's substitute these values into the acceleration formula:

a = Δv / Δt
a = 0 / 1
a = 0 m/s²

Hence, the acceleration of the object is 0 m/s². This indicates that the object is moving at a constant speed with no change in velocity.

To find the acceleration in meters per second per second, we need to determine the change in velocity over time.

Since the object travels 8 m in every second, its velocity does not change. Therefore, the change in velocity is 0 m/s.

Acceleration is defined as the change in velocity divided by the change in time. Given that the velocity change is 0, divided by any time interval, the result will always be 0.

Hence, the correct answer is that the acceleration is 0 meters per second per second.