Find the resultant of the following two displacements; 2.0 m 40 degrees 4.0 meters at 127 degrees. the angles are taken relative to the x-axis
2cos40+4cos127=-0.875
2sin40+4sin127=4.481
R=A+B
=-0.875+4.481
=3.6m
x component = 2 cos 40 + 4 cos 127
y component = 2 sin 40 + 4 sin 127
magnitude = sqrt(x^2+y^)
tan^-1 A = y/x
where A = angle from x axis
lay out the
displacements to scale, tip to tail from the origin. Notice that all
angles are measured from the +x-axis. The resultant vector
points from starting point to end point as shown. We measure its
length on the scale diagram to find its magnitude, 4.6 m. Using a
protractor, we measure its angle θ to be 101°. The resultant
displacement is therefore 4.6 m at 101°