How much force will be required to move a seesaw system which is balanced with 50 kg weight on both side to move it 4 centimeter towards up and down side (linear motion).
huh? if it is balanced then zero.
To calculate the force required to move a balanced seesaw system, we need to consider the weight distribution and leverage of the system. In this case, the seesaw is balanced with a 50 kg weight on both sides.
First, let's assume that the seesaw is in equilibrium initially, meaning it is perfectly balanced and not moving. In this state, the forces on both sides of the seesaw are equal. The weight of the 50 kg mass provides a downward force due to gravity, which can be calculated using the formula:
Force = mass × acceleration due to gravity
Force = 50 kg × 9.8 m/s² (acceleration due to gravity)
Force = 490 N
Since the seesaw is balanced, each side carries an equal force of 490 N.
Now, let's consider the motion of the seesaw when it is moved 4 centimeters towards the up and down sides in a linear motion. We need to account for the leverage or moment arm of the seesaw.
The moment arm is the perpendicular distance from the pivot point (fulcrum) to the line of action of the force. In this case, moving the seesaw 4 centimeters requires the application of a force at the end of the seesaw, farthest from the pivot point.
To calculate the force required at this distance, we can use the principle of moments, which states that the total moments on both sides of a balanced system are equal.
Moment = Force × Distance
In this case, the moments on both sides of the seesaw should be equal to maintain equilibrium.
Let's assume a fulcrum sits at the center of the seesaw, meaning the balance point is at a distance of 2 centimeters from the pivot point to each side.
The moment on one side of the seesaw can be calculated as follows:
Moment = Force × Distance
Moment = 490 N × 0.02 meters (conversion from centimeters to meters)
Moment = 9.8 Nm
Since the system is balanced, the total moment on the other side of the seesaw is also 9.8 Nm.
Now, let's calculate the force required to create a moment of 9.8 Nm on the opposite side of the seesaw.
Force = Moment / Distance
Force = 9.8 Nm / 0.04 meters
Force = 245 N
Therefore, the force required to move the balanced seesaw system 4 centimeters towards the up and down sides is approximately 245 Newtons.