How much heat energy is required to heat up 50.0 grams of water from 20.2 degrees Celsius to 34.2 degrees Celsius? I want o use the Q=mc(change in temp) formula but I am only given the m and difference in temp in this question so I am not sure of what I am supposed to do.
Hi. Well, what is the specific heat capacity of water? use that number to plug into Q=M(c)(delta T) with the rest of your information.
In this problem its given in grams, so you use 4.19 J/g C
2926J
To calculate the amount of heat energy required to heat up a substance, you can use the formula Q = mcΔT, where:
Q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in joules/gram°C)
ΔT = change in temperature (in °C)
In this case, you have the mass (m = 50.0 grams) and the change in temperature (ΔT = 34.2°C - 20.2°C = 14.0°C), but you are uncertain about the specific heat capacity (c).
The specific heat capacity of water is approximately 4.18 J/g°C. This means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Now that you know the specific heat capacity of water, you can use the formula Q = mcΔT to find the amount of heat energy required to heat up the water:
Q = (50.0 grams) x (4.18 J/g°C) x (14.0°C)
Calculating the above expression will give you the amount of heat energy required in joules.