How much work is required to lift a bag of wheat (mass 50kg) to a height of 2.4m?
** Answer is 1200J, but I keep getting 1176J.
50 * 9.81 * 2.4 = about 1200 J
If you say g = 10m/s^2 you get exactly 1200 J
To find the amount of work required to lift a bag of wheat, we need to use the formula for work: Work = Force x Distance.
In this case, the bag of wheat has a mass of 50 kg. The force required to lift an object is equal to the weight of the object, which can be calculated using the formula: Weight = mass x gravitational acceleration.
The gravitational acceleration on Earth is approximately 9.8 m/s^2.
So, the weight of the bag of wheat is: Weight = 50 kg x 9.8 m/s^2.
Now we can calculate the work: Work = Force x Distance.
The distance is given as 2.4 m.
Therefore, the work required to lift the bag of wheat to a height of 2.4 m is:
Work = (Weight)x(Distance) = (50 kg x 9.8 m/s^2) x (2.4 m).
To solve the equation, multiply the weight by the distance: Work = (50 kg x 9.8 m/s^2) x (2.4 m).
Work = 1176 Joules.
Therefore, 1176 Joules of work is required to lift the bag of wheat to a height of 2.4 m.