Define the inverse secant function by restricting the domain of the secant function to the intervals (0, pi/2) and (pi/2, pi), and sketch the inverse function’s graph.

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  1. sec = 1/cos
    note cos is 0 at pi/2 so sec is undefined there (infinite + or -)
    in quadrant I cos is + so sec is +
    but in quadrant II cos is - so sec is -

    note cos always </= |1| so |sec| always >/= |1|

    that should help with your graph

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