Chemistry

If 20.00 mL of 0.2019 M HCl requires 39.63 mL of a NaOH solution for complete neutralization, what is the concentration of the NaOH solutions? How many significant figures are justified in the answer?

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  1. The equation is
    HCl + NaOH ==> NaCl + H2O

    mols HCl = M x L
    Convert mols HCl to mols NaOH from the equation.
    M(NaOH) = #mols/L.
    You have mols and L, solve for M.
    Post your work if you get stuck.

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  2. .1019M NaOH 4 sig figs

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  3. HCl + NaOH ==> NaCl + H2O

    (Don't forget to convert mL to L)

    .2019M HCl = mol/L
    solve for mol
    Answer mol HCL = .02L * .2019M

    1-1 ratio based on equation: (Answer mol HCL/1) * (1 mol HCL/ 1 mol KHP) = Answer mol HCl

    using molarity equation, mol/L = M
    solve for M
    Answer mol HCL/ .03963 L = Final Answer M NaOH

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    posted by Leslie
  4. ** Correction**

    HCl + NaOH ==> NaCl + H2O

    (Don't forget to convert mL to L)
    (Use M=(mol/L)

    .2019M HCl = mol/L
    solve for mol
    Answer mol HCL = .02L * .2019M

    1-1 ratio based on equation: (Answer mol HCL/1) * (1 mol NaOH/ 1 mol HCl) = Answer mol NaOH

    using molarity equation, mol/L = M
    solve for M
    Answer mol NaOH/ .03963 L = Final Answer M NaOH

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    2. 👎 0
    posted by Leslie

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