Odell has the same numbers of quarters, dimes and nickels. In all he has $4 in change. How man of each coin does he have?
10
10 quarters
10 dimes
10 nicklels
To find the number of quarters, dimes, and nickels that Odell has, we can set up an equation based on the information given.
Let's assume the number of each coin Odell has is represented by the variables q (quarters), d (dimes), and n (nickels).
From the problem, it is given that Odell has the same number of quarters, dimes, and nickels. Therefore, we have:
q = d = n
Next, we can determine the value of each coin.
A quarter is worth $0.25, a dime is worth $0.10, and a nickel is worth $0.05.
The total value of the change Odell has is given as $4.
Based on this information, we can construct the equation:
0.25q + 0.10d + 0.05n = 4
Since we know that Odell has the same number of quarters, dimes, and nickels, we can substitute q = d = n into the equation:
0.25(q) + 0.10(q) + 0.05(q) = 4
Simplifying the equation, we get:
0.40q = 4
Dividing both sides by 0.40, we find:
q = 10
So, Odell has 10 quarters.
Since the number of quarters, dimes, and nickels is the same, he also has:
d = 10
n = 10
Thus, Odell has 10 quarters, 10 dimes, and 10 nickels.